Radiator ΔT converter

The calculator needs JavaScript. The worked example, formula and figures below show exactly how it works, so you can do the sum yourself. A guide, not advice. Check your supplier's or maker's figures before ordering.

Short answer

Worked example

Worked example inputs
You enterValue
What do you know?The ΔT50 rating
Output at ΔT502,000 W
ΔT30 K
Radiator exponent n1.3

Output at ΔT30: 1,030 W

Worked example results
ResultValue
Output at your ΔT1,030 W (3,513 BTU/h)
Output at ΔT502,000 W (6,824 BTU/h)
Correction factor (ΔT ÷ 50)^n0.515
Output at other ΔTs
ΔTFactorOutput
20 K0.304608 W
25 K0.406812 W
30 K0.5151,030 W
35 K0.6291,258 W
40 K0.7481,496 W
45 K0.8721,744 W
50 K12,000 W
55 K1.1322,264 W
60 K1.2672,535 W
Show the working
  1. Correction factor: (30 ÷ 50)^1.3 = 0.515
  2. Output at ΔT30: 2,000 W × 0.515 = 1,030 W

How it works

  1. Correction factor = (ΔT ÷ 50)^n, where ΔT = mean water temperature − room temperature and n is the radiator exponent
  2. Output at your ΔT = ΔT50 output × correction factor
  3. ΔT50 output = output at your ΔT ÷ correction factor

Our exponent n is a typical figure; use the maker's own n or their correction table where they give one.

Our default (adjustable)

These are typical planning figures and our own allowances, not facts about your product. Change any of them in the calculator to match your bag, pack or tin.

FigureOur default (adjustable)KindSource
Radiator exponent n1.3 Our assumption
Not yet checked against the source
Our choice: change it to suit your job
Radiator exponent n, default 1.3 as stated in brief v2 H2 ("typical from makers"). Stored as an assumption until the Researcher cites a maker's data sheet (e.g. Stelrad, Zehnder) and switches it to typical.

Regulations and standards

  • BS EN 442 (radiator outputs rated at ΔT50)

Explained: BS EN 442 (radiators).

Our checks use the guidance for England unless a badge says otherwise. Wales, Scotland and Northern Ireland have their own rules: check the source for where you live.

FAQs